Problem Number: 14 Difficulty: Easy Category: String, Trie LeetCode Link: https://leetcode.com/problems/longest-common-prefix/
Write a function to find the longest common prefix string amongst an array of strings.
If there is no common prefix, return an empty string "".
Example 1:
Input: strs = ["flower","flow","flight"]
Output: "fl"
Example 2:
Input: strs = ["dog","racecar","car"]
Output: ""
Explanation: There is no common prefix among the input strings.
Constraints:
1 <= strs.length <= 2000 <= strs[i].length <= 200strs[i]consists of only lowercase English letters
I used a Character-by-Character Comparison approach. The key insight is to compare characters at the same position across all strings, starting from the first character, and stop when we find a mismatch or reach the end of any string.
Algorithm:
- Handle edge cases (empty array, single string)
- Find the minimum length among all strings
- Truncate all strings to the minimum length
- Compare characters at each position across all strings
- Stop when a mismatch is found
- Return the common prefix found so far
The solution uses character-by-character comparison with optimization. See the implementation in the solution file.
Key Points:
- Finds minimum length to avoid index out of bounds
- Truncates all strings to minimum length for efficiency
- Compares characters at each position across all strings
- Stops at first mismatch and returns prefix up to that point
Time Complexity: O(S)
- S is the sum of all characters in all strings
- We compare each character at most once
- Finding minimum length: O(n)
- Character comparisons: O(S)
Space Complexity: O(1)
- Uses only a constant amount of extra space
- No additional data structures proportional to input size
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Character-by-Character Comparison: The longest common prefix must match at every position across all strings.
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Minimum Length Optimization: By finding the minimum length, we avoid unnecessary comparisons beyond the shortest string.
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Early Termination: We can stop as soon as we find a mismatch at any position.
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String Truncation: Truncating strings to minimum length simplifies the comparison logic.
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Edge Cases: Empty array returns empty string, single string returns itself.
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No Common Prefix: If the first characters don't match, there's no common prefix.
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Inefficient Comparison: Initially might compare entire strings instead of character by character.
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Missing Edge Cases: Not properly handling empty array or single string cases.
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Index Out of Bounds: Not considering that strings might have different lengths.
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Unnecessary Complexity: Overcomplicating the solution with data structures like Trie.
- Implement Trie (Problem 208): Data structure for efficient string operations
- Word Search (Problem 79): Finding words in a 2D grid
- Valid Parentheses (Problem 20): Pattern matching with symbols
- Group Anagrams (Problem 49): Grouping strings by their characteristics
- Horizontal Scanning: Compare first two strings, then result with next string
- Vertical Scanning: Compare characters at same position across all strings
- Divide and Conquer: Split array in half, find LCP of each half, then combine
- Binary Search: Use binary search on the length of the common prefix
- Index Out of Bounds: Not handling strings of different lengths properly.
- Inefficient Comparison: Comparing entire strings instead of character by character.
- Missing Edge Cases: Not handling empty array or single string.
- Over-engineering: Using complex data structures when simple comparison suffices.
- Wrong Termination: Not stopping at the first mismatch.
Note: This is a fundamental string problem that introduces the concept of finding common patterns across multiple strings.