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101_isSymmetric.cpp
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68 lines (67 loc) · 1.51 KB
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/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
/**
递归解法
**/
class Solution {
public:
bool judge(TreeNode *p,TreeNode *q){
if(p == NULL&&q == NULL)
return true;
if(p==NULL||q == NULL)
return false;
if(p->val != q->val)
return false;
return judge(p->left,q->right)&&judge(p->right,q->left);
}
bool isSymmetric(TreeNode* root) {
if(root == NULL)
return true;
return judge(root->left,root->right);
}
};
/**
迭代解法
**/
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
bool isSymmetric(TreeNode* root) {
queue<TreeNode*> que;
que.push(root);
que.push(root);
TreeNode *p,*q;
while(!que.empty()){
p = que.front();
que.pop();
q = que.front();
que.pop();
if(p == NULL&&q==NULL)
continue;
if(p == NULL||q == NULL)
return false;
if(p->val!=q->val)
return false;
que.push(p->left);
que.push(q->right);
que.push(p->right);
que.push(q->left);
}
return true;
}
};