basicCalculator.js

// Tag:- bugs functional_programming language_fundamentals numbers 

/*
**Question:
Mubashir created a function that takes two numbers a and b and an operator o.
His function should return the result of the corresponding mathematical function
on both numbers. If the operator is not one of the specified characters +, -, /, *,
or if there is a division by zero, the function should return null. Help him by
fixing the code in the code tab to pass this challenge.

Look at the examples below to get an idea of what the function should do:

// Examples
basicCalculator(2, '+',  4) ➞ 6
basicCalculator(6, '-', 5) ➞ 1
basicCalculator(12, '/', 3) ➞ 4
basicCalculator(3, '*', 4) ➞ 12
basicCalculator(1, '/', 0) ➞ null
// Division by zero is not possible
basicCalculator(1, 'x', 0) ➞ null
// 'x' is not an operator
*/


var test = require('./test/test.js');

function basicCalculator(a, o, b) {
	 //var result = 0;
   if(o === "/" && b === 0) {
	   return null;
   }else if(o === "+") {
	   return a + b;
   }else if(o === "-") {
		 return a - b;
	 }else if(o === "/") {
     return a/b;
   }else if(o === "*") {
	   return a * b;
   }else {
     return null;
   }
}


// Unit Test
let Test = new test();

Test.assertEquals(basicCalculator(12, '-', 6), 6)
Test.assertEquals(basicCalculator(18, '/', 2), 9)
Test.assertEquals(basicCalculator(6, '*', 4), 24)
Test.assertEquals(basicCalculator(2, '/', 0), null)
Test.assertEquals(basicCalculator(2, 'x', 4), null)
Test.assertEquals(basicCalculator(2, 'o', 4), null)
Test.assertEquals(basicCalculator(12, '-', 2), 10)
Test.assertEquals(basicCalculator(17, '*', 2), 34)