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1878.cpp
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64 lines (63 loc) · 1.93 KB
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class Solution {
public:
int getSum(int y, int x, int size, vector<vector<int>>& grid) {
int m = grid.size();
int n = grid[0].size();
if (y - size < 0) return -1;
if (y + size >= m) return -1;
if (x - size < 0) return -1;
if (x + size >= n) return -1;
if (size == 0) return grid[y][x];
// up (y - size, x)
// left (y, x - size)
// down (y + size, x)
// right (y, x + size)
int sum = 0;
int diag = x + y - size;
int revDiag = y - x + size;
for (int i = 0; i < size; ++i) {
int currY = y - size + i;
int currX = diag - currY;
sum += grid[currY][currX];
}
for (int i = 0; i < size; ++i) {
int currY = y + i;
int currX = currY - revDiag;
sum += grid[currY][currX];
}
diag = x + y + size;
revDiag = y - x - size;
for (int i = 0; i < size; ++i) {
int currY = y + size - i;
int currX = diag - currY;
sum += grid[currY][currX];
}
for (int i = 0; i < size; ++i) {
int currY = y - i;
int currX = currY - revDiag;
sum += grid[currY][currX];
}
return sum;
}
vector<int> getBiggestThree(vector<vector<int>>& grid) {
int m = grid.size();
int n = grid[0].size();
set<int> st;
for (int i = 0; i < m; ++i) {
for (int j = 0; j < n; ++j) {
for (int k = 0; k * 2 + 1 <= min(m, n); ++k) {
int sum = getSum(i, j, k, grid);
if (sum != -1) {
st.insert(sum);
}
}
}
}
vector<int> res;
for (auto it = st.rbegin(); it != st.rend(); ++it) {
res.push_back(*it);
if (res.size() >= 3) break;
}
return res;
}
};