⚙문제보기
🔎문제 풀이 MySQL
(
SELECT name AS 'results'
FROM MovieRating r JOIN Users u ON r.user_id = u.user_id
GROUP BY r.user_id
ORDER BY COUNT(*) DESC, 1
LIMIT 1
)
UNION ALL
(
SELECT title AS 'results'
FROM MovieRating r JOIN Movies m ON r.movie_id = m.movie_id
WHERE created_at LIKE '2020-02%'
GROUP BY r.movie_id
ORDER BY AVG(rating) DESC, 1
LIMIT 1
)