Refactor palindrome check to O(1) space mathematical approach

Author: YASWANTH1976

maths/palindrome_number.py

@@ -1,11 +1,23 @@
 def is_palindrome(number: int) -> bool:
     """
-    Determines if an integer is a palindrome without string conversion.
+    Determines if an integer is a palindrome without using string conversion.
 
     Logic:
-    1. Filter out negative numbers and multiples of 10.
-    2. Reverse the second half of the number.
-    3. Compare the two halves.
+    1. Negative numbers are not palindromes.
+    2. Numbers ending in 0 (except 0 itself) are not palindromes.
+    3. Reverse half of the number and compare.
+
+    Examples:
+    >>> is_palindrome(121)
+    True
+    >>> is_palindrome(12321)
+    True
+    >>> is_palindrome(10)
+    False
+    >>> is_palindrome(-121)
+    False
+    >>> is_palindrome(0)
+    True
     """
     if number < 0 or (number % 10 == 0 and number != 0):
         return False