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inversion of an array
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55 lines (51 loc) · 1.28 KB
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#include <iostream>
#include <vector>
using std::vector;
long long get_inversions(vector<int> &a, vector<int> &b, size_t left, int ave, size_t right) {
size_t i = left, j = ave, k = left;
long long inv_count = 0;
while (i <= ave - 1 && j <= right) {
if (a[i] <= a[j]) {
b[k] = a[i];
i++;
} else {
b[k] = a[j];
inv_count += ave - i;
j++;
}
k++;
}
while (i <= ave - 1) {
b[k] = a[i];
i++;
k++;
}
while (j <= right) {
b[k] = a[j];
j++;
k++;
}
for (i = left; i <= right; i++) {
a[i] = b[i];
}
return inv_count;
}
long long merge_sort(vector<int> &a, vector<int> &b, size_t left, size_t right) {
long long inv_count = 0;
if (right <= left) return inv_count;
size_t ave = left + (right - left) / 2;
inv_count += merge_sort(a, b, left, ave);
inv_count += merge_sort(a, b, ave + 1, right);
inv_count += get_inversions(a, b, left, ave + 1, right);
return inv_count;
}
int main() {
int n;
std::cin >> n;
vector<int> a(n);
for (size_t i = 0; i < a.size(); i++) {
std::cin >> a[i];
}
vector<int> b(a.size());
std::cout << merge_sort(a, b, 0, a.size() - 1) << '\n';
}