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867-TransposeMatrix.go
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99 lines (87 loc) · 2.21 KB
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package main
// 867. Transpose Matrix
// Given a 2D integer array matrix, return the transpose of matrix.
// The transpose of a matrix is the matrix flipped over its main diagonal, switching the matrix's row and column indices.
// <img src="https://assets.leetcode.com/uploads/2021/02/10/hint_transpose.png" / >
// [1,2,3] [1,4,7]
// [4,5,6] => [2,5,8]
// [7,8,9] [3,6,9]
// Example 1:
// Input: matrix = [[1,2,3],[4,5,6],[7,8,9]]
// Output: [[1,4,7],[2,5,8],[3,6,9]]
// Example 2:
// Input: matrix = [[1,2,3],[4,5,6]]
// Output: [[1,4],[2,5],[3,6]]
// Constraints:
// m == matrix.length
// n == matrix[i].length
// 1 <= m, n <= 1000
// 1 <= m * n <= 10^5
// -10^9 <= matrix[i][j] <= 10^9
import "fmt"
func transpose(matrix [][]int) [][]int {
// 造一个全0的结果
res := make([][]int, len(matrix[0]))
for i := 0; i < len(matrix[0]); i++ {
t := make([]int,len(matrix))
res[i] = t
}
for i := 0; i < len(matrix); i++ {
for j := 0; j < len(matrix[0]); j++ {
res[j][i] = matrix[i][j]
}
}
return res
}
func transpose1(matrix [][]int) [][]int {
n,m := len(matrix),len(matrix[0])
t := make([][]int,m)
for i := range t{
t[i] = make([]int,n)
for j := range t[i] {
t[i][j] = -1
}
}
for i,row := range matrix{
for j,v := range row{
t[j][i] =v
}
}
return t
}
func main() {
fmt.Println(
transpose(
[][]int {
[]int{ 1,2,3 },
[]int{ 4,5,6 },
[]int{ 7,8,9 },
},
),
) // [[1,4,7],[2,5,8],[3,6,9]]
fmt.Println(
transpose(
[][]int {
[]int{ 1,2,3 },
[]int{ 4,5,6 },
},
),
) // [[1,4],[2,5],[3,6]]
fmt.Println(
transpose1(
[][]int {
[]int{ 1,2,3 },
[]int{ 4,5,6 },
[]int{ 7,8,9 },
},
),
) // [[1,4,7],[2,5,8],[3,6,9]]
fmt.Println(
transpose1(
[][]int {
[]int{ 1,2,3 },
[]int{ 4,5,6 },
},
),
) // [[1,4],[2,5],[3,6]]
}