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905-SortArrayByParity.go
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75 lines (66 loc) · 1.78 KB
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package main
// 905. Sort Array By Parity
// Given an integer array nums, move all the even integers at the beginning of the array followed by all the odd integers.
// Return any array that satisfies this condition.
// Example 1:
// Input: nums = [3,1,2,4]
// Output: [2,4,3,1]
// Explanation: The outputs [4,2,3,1], [2,4,1,3], and [4,2,1,3] would also be accepted.
// Example 2:
// Input: nums = [0]
// Output: [0]
// Constraints:
// 1 <= nums.length <= 5000
// 0 <= nums[i] <= 5000
import "fmt"
func sortArrayByParity(nums []int) []int {
for i, j := 0, 0; j < len(nums); j++ {
if nums[j] % 2 == 0 { // 如果是偶数交换到前面去
// t := nums[i]
// nums[i] = nums[j]
// nums[j] = t
nums[i],nums[j] = nums[j], nums[i]
i++
}
}
return nums
}
func sortArrayByParity1(nums []int) []int {
odd, even:= map[int]int{}, map[int]int{}
for _, v := range nums {
if v % 2 == 1 {
odd[v]++
} else {
even[v]++
}
}
i := 0
for k, v := range even {
for v > 0 {
nums[i] = k
i++
v--
}
}
for k, v := range odd {
for v > 0 {
nums[i] = k
i++
v--
}
}
return nums
}
func main() {
// Example 1:
// Input: nums = [3,1,2,4]
// Output: [2,4,3,1]
// Explanation: The outputs [4,2,3,1], [2,4,1,3], and [4,2,1,3] would also be accepted.
fmt.Println(sortArrayByParity([]int{3,1,2,4})) // [2,4,3,1]
// Example 2:
// Input: nums = [0]
// Output: [0]
fmt.Println(sortArrayByParity([]int{0})) // [0]
fmt.Println(sortArrayByParity1([]int{3,1,2,4})) // [2,4,3,1]
fmt.Println(sortArrayByParity1([]int{0})) // [0]
}