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KeysAndRooms_841.java
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75 lines (67 loc) · 2.16 KB
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package com.leetcode.problems.medium;
import java.util.*;
/**
* @author neeraj on 10/09/19
* Copyright (c) 2019, data-structures.
* All rights reserved.
*/
public class KeysAndRooms_841 {
public static void main(String[] args) {
solveProblem(new int[][]
{{4}, {3}, {}, {2, 5, 7}, {1}, {}, {8, 9}, {}, {}, {6}}
);
solveProblem(new int[][]{
{1},{2},{3},{}
});
}
public static boolean canVisitAllRooms(List<List<Integer>> rooms) {
Set<Integer> visited = new HashSet<>();
visitRooms(rooms, 0, visited);
System.out.println(visited);
return visited.size() == rooms.size();
}
public static void visitRooms(List<List<Integer>> rooms, int room, Set<Integer> visited) {
visited.add(room);
for(Integer roomToVisit: rooms.get(room)) {
if(!visited.contains(roomToVisit)) {
visitRooms(rooms, roomToVisit, visited);
}
}
visited.remove(room);
}
private static void solveProblem(int[][] inputs) {
List<List<Integer>> rooms = new ArrayList<>();
List<Integer> keys;
for (int i = 0; i < inputs.length; i++) {
keys = new ArrayList<>();
for (int j = 0; j < inputs[i].length; j++) {
keys.add(inputs[i][j]);
}
rooms.add(keys);
}
System.out.println("Can visit all rooms ? " + canVisitAllRooms(rooms));
}
//
// public static boolean canVisitAllRooms(List<List<Integer>> rooms) {
// // To avoid visiting the room already visited.
// Set<Integer> visitedRooms = new HashSet<>();
// visitedRooms.add(0);
//
// Stack<Integer> dfs = new Stack<>();
// dfs.add(0);
// Integer polledKey;
//
// while (!dfs.isEmpty()) {
//
// List<Integer> polledKeys = rooms.get(dfs.pop());
//
// for(Integer key: polledKeys) {
// if(!visitedRooms.contains(key)) {
// visitedRooms.add(key);
// dfs.add(key);
// }
// }
// }
// return visitedRooms.size() == rooms.size();
// }
}