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0102-binary-tree-level-order-traversal.cpp
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41 lines (38 loc) · 1.14 KB
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/*
102. Binary Tree Level Order Traversal
Submitted: January 13, 2024
Runtime: 0 ms (beats 100.00%)
Memory: 17.24 MB (beats 14.20%)
*/
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
vector<vector<int>> levelOrder(TreeNode* root) {
if (root == nullptr) return {};
vector<vector<int>> res;
deque<TreeNode*> queue;
queue.push_front(root);
while (!queue.empty()) {
vector<int> v;
for (int i = 0, n = queue.size(); i < n; ++i) {
TreeNode* p = queue.back();
queue.pop_back();
v.push_back(p->val);
if (p->left != nullptr) queue.push_front(p->left);
if (p->right != nullptr) queue.push_front(p->right);
}
res.push_back(v);
}
return res;
}
};