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35.search-insert-position.cpp
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75 lines (74 loc) · 1.38 KB
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/*
* @lc app=leetcode id=35 lang=cpp
*
* [35] Search Insert Position
*
* https://leetcode.com/problems/search-insert-position/description/
*
* algorithms
* Easy (42.20%)
* Likes: 9233
* Dislikes: 456
* Total Accepted: 1.6M
* Total Submissions: 3.9M
* Testcase Example: '[1,3,5,6]\n5'
*
* Given a sorted array of distinct integers and a target value, return the
* index if the target is found. If not, return the index where it would be if
* it were inserted in order.
*
* You must write an algorithm with O(log n) runtime complexity.
*
*
* Example 1:
*
*
* Input: nums = [1,3,5,6], target = 5
* Output: 2
*
*
* Example 2:
*
*
* Input: nums = [1,3,5,6], target = 2
* Output: 1
*
*
* Example 3:
*
*
* Input: nums = [1,3,5,6], target = 7
* Output: 4
*
*
*
* Constraints:
*
*
* 1 <= nums.length <= 10^4
* -10^4 <= nums[i] <= 10^4
* nums contains distinct values sorted in ascending order.
* -10^4 <= target <= 10^4
*
*
*/
// @lc code=start
class Solution
{
public:
int searchInsert(vector<int> &nums, int target)
{
int i = 0, j = nums.size() - 1;
for (int k = (i + j) / 2; i <= j; k = (i + j) / 2)
{
if (nums[k] == target)
return k;
else if (nums[k] < target)
i = k + 1;
else
j = k - 1;
}
return i;
}
};
// @lc code=end