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37 lines (25 loc) · 781 Bytes
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You are given a large integer represented as an integer array digits, where each digits[i] is the ith digit of the integer. The digits are ordered from most significant to least significant in left-to-right order. The large integer does not contain any leading 0's.
Increment the large integer by one and return the resulting array of digits.
Example 1:
Input: digits = [1,2,3]
Output: [1,2,4]
Explanation: The array represents the integer 123.
Incrementing by one gives 123 + 1 = 124.
Thus, the result should be [1,2,4].
#include <iostream>
using namespace std;
int main()
{
int n,rem;
cin>>n;
int a[n];
for(int i=0;i<n;i++){
cin>>a[i];
rem = a[i]%10;
}
rem= rem+1;
a[n-1] = rem;
for(int i=0;i<n;i++){
cout<<a[i];
}
}