diff --git a/Problem1.cs b/Problem1.cs
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--- /dev/null
+++ b/Problem1.cs
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+// Time Complexity : O(n) ammortized time complexity
+// Space Complexity : O(n)
+// Did this code successfully run on Leetcode : Yes
+// Any problem you faced while coding this : No
+
+
+// Your code here along with comments explaining your approach
+
+/*
+I maintian two stacks - an in-stack which is solely used for pushing elements into the queue and an out-stack which is solely used for
+removing elements from the queue. Every insert operation into the queue is performed by pushing the element to the in-stack.
+Before performing any pop/peek operation, we check if out-stack is empty, if so then we transfer all the elements from in stack to out stack.
+Every peek and pop operation is performed on the out stack.
+*/
+
+public class MyQueue
+{
+    Stack<int> inStack;
+    Stack<int> outStack;
+
+    public MyQueue()
+    {
+        inStack = new();
+        outStack = new();
+    }
+
+    public void Push(int x)
+    {
+        inStack.Push(x);
+    }
+
+    public int Pop()
+    {
+        if (outStack.Count == 0)
+        {
+            Transfer();
+        }
+
+        return outStack.Pop();
+    }
+
+    public int Peek()
+    {
+        if (outStack.Count == 0)
+        {
+            Transfer();
+        }
+
+        return outStack.Peek();
+    }
+
+    public bool Empty()
+    {
+        return inStack.Count == 0 && outStack.Count == 0;
+    }
+
+    private void Transfer()
+    {
+        while (inStack.Count != 0)
+        {
+            outStack.Push(inStack.Pop());
+        }
+    }
+}
+
+/**
+ * Your MyQueue object will be instantiated and called as such:
+ * MyQueue obj = new MyQueue();
+ * obj.Push(x);
+ * int param_2 = obj.Pop();
+ * int param_3 = obj.Peek();
+ * bool param_4 = obj.Empty();
+ */
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diff --git a/Problem2.cs b/Problem2.cs
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--- /dev/null
+++ b/Problem2.cs
@@ -0,0 +1,95 @@
+// Time Complexity : O(1)
+// Space Complexity : O(n)
+// Did this code successfully run on Leetcode : Yes
+// Any problem you faced while coding this : No
+
+
+// Your code here along with comments explaining your approach
+
+/*
+I have implemented a hashmap using double hashing. By default, each bucket is allocated the value -1. If a key is not present, I return
+-1 to the user. If key exists in the hashmap, the corresponding value is returned to the user if it's present, or -1 is returned.
+*/
+
+public class MyHashMap
+{
+    private int[][] buckets;
+    private int bucketCount;
+    private int bucketSize;
+
+    public MyHashMap()
+    {
+        bucketCount = 1000;
+        bucketSize = 1000;
+        buckets = new int[bucketCount][];
+    }
+
+    public void Put(int key, int value)
+    {
+        int hash1 = HashFunction1(key);
+
+        if (buckets[hash1] == null)
+        {
+            if (hash1 == 0)
+            {
+                buckets[hash1] = new int[bucketSize + 1];
+            }
+
+            else
+            {
+                buckets[hash1] = new int[bucketSize];
+            }
+
+            Array.Fill(buckets[hash1], -1);
+        }
+
+        int hash2 = HashFunction2(key);
+
+        buckets[hash1][hash2] = value;
+
+    }
+
+    public int Get(int key)
+    {
+        int hash1 = HashFunction1(key);
+
+        if (buckets[hash1] == null)
+        {
+            return -1;
+        }
+
+        int hash2 = HashFunction2(key);
+
+        return buckets[hash1][hash2];
+    }
+
+    public void Remove(int key)
+    {
+        int hash1 = HashFunction1(key);
+
+        if (buckets[hash1] != null)
+        {
+            int hash2 = HashFunction2(key);
+
+            buckets[hash1][hash2] = -1;
+        }
+    }
+
+    private int HashFunction1(int key)
+    {
+        return key % bucketCount;
+    }
+
+    private int HashFunction2(int key)
+    {
+        return key / bucketSize;
+    }
+}
+
+/**
+ * Your MyHashMap object will be instantiated and called as such:
+ * MyHashMap obj = new MyHashMap();
+ * obj.Put(key,value);
+ * int param_2 = obj.Get(key);
+ * obj.Remove(key);
+ */
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