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Binary_Tree_Preorder_Traversal.cpp
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62 lines (54 loc) · 1.26 KB
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// Source : https://oj.leetcode.com/problems/binary-tree-preorder-traversal/
// Author : zheng yi xiong
// Date : 2014-11-22
/**********************************************************************************
*
* Given a binary tree, return the preorder traversal of its nodes' values.
* For example:
* Given binary tree {1,#,2,3},
* 1
* \
* 2
* /
* 3
* return [1,2,3].
* Note: Recursive solution is trivial, could you do it iteratively?
*
**********************************************************************************/
struct TreeNode {
int val;
TreeNode *left;
TreeNode *right;
TreeNode(int x) : val(x), left(NULL), right(NULL) {}
};
class Solution {
public:
vector<int> preorderTraversal(TreeNode *root) {
vector<int> preorder_vec;
if (NULL == root)
{
return preorder_vec;
}
stack<TreeNode *> preorder_stack;
preorder_stack.push(NULL);
TreeNode *pTempNode = root;
while (NULL != pTempNode)
{
preorder_vec.push_back(pTempNode->val);
if (NULL != pTempNode->right)
{
preorder_stack.push(pTempNode->right);
}
if (NULL != pTempNode->left)
{
pTempNode = pTempNode->left;
}
else
{
pTempNode = preorder_stack.top();
preorder_stack.pop();
}
}
return preorder_vec;
}
};