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Time - Yolotzin #21
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Time - Yolotzin #21
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| Original file line number | Diff line number | Diff line change |
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| @@ -1,8 +1,25 @@ | ||
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| # This method uses a heap to sort an array. | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| # Time Complexity: O(n log n) | ||
| # Space Complexity: O(n) | ||
| def heap_sort(list) | ||
| raise NotImplementedError, "Method not implemented yet..." | ||
| end | ||
| if list.size < 2 | ||
| return list | ||
| end | ||
| heap = MinHeap.new | ||
| list.each do |element| | ||
| heap.add(element) | ||
| end | ||
| result = [] | ||
| list.size.times do | ||
| result << heap.remove | ||
| end | ||
| return result | ||
| end | ||
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| # Since you do n additions and adding 1 item to a heap is O(log n), filling up the heap is O(n log n). | ||
| # Then removing all n item is O(n log n) because removing one item from a heap is O(log n). | ||
| # So the total Time Complexity is O(n log n + n log n) = O(n log n) | ||
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| # you can do HeapSort with O(1) space complexity (using the original array for the heap). | ||
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@@ -7,25 +7,33 @@ def initialize(key, value) | |
| end | ||
| end | ||
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| class MinHeap | ||
| class MinHeap # every node is smaller than or equal to it's children | ||
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| def initialize | ||
| @store = [] | ||
| end | ||
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| # This method adds a HeapNode instance to the heap | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| # Time Complexity: O(log n) | ||
| # Space Complexity: O(n) | ||
| def add(key, value = key) | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 , However your space complexity due to the tree structure and recursion is O(log n) |
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| raise NotImplementedError, "Method not implemented yet..." | ||
| @store << HeapNode.new(key, value) | ||
| heap_up(@store.length - 1) | ||
| end | ||
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| # This method removes and returns an element from the heap | ||
| # maintaining the heap structure | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| # Time Complexity: O(log n) | ||
| # Space Complexity: O(n) | ||
| def remove() | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 Ditto on space complexity. |
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| raise NotImplementedError, "Method not implemented yet..." | ||
| return nil if @store.empty? | ||
| # swap the root node and last leaf | ||
| swap(0, @store.length - 1) | ||
| # delete the last leaf | ||
| result = @store.pop | ||
| # start heap_down with the new root | ||
| heap_down(0) unless @store.empty? | ||
| return result.value | ||
| end | ||
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@@ -44,28 +52,61 @@ def to_s | |
| end | ||
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| # This method returns true if the heap is empty | ||
| # Time complexity: ? | ||
| # Space complexity: ? | ||
| # Time complexity: O(1) | ||
| # Space complexity: O(1) | ||
| def empty? | ||
| raise NotImplementedError, "Method not implemented yet..." | ||
| return @store.size == 0 | ||
| end | ||
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| private | ||
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| # This helper method takes an index and | ||
| # moves it up the heap, if it is less than it's parent node. | ||
| # It could be **very** helpful for the add method. | ||
| # Time complexity: ? | ||
| # Space complexity: ? | ||
| # Time complexity: O(log n) | ||
| # Space complexity: O(n) | ||
| def heap_up(index) | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 |
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| # base case: if we hit root | ||
| return if index == 0 | ||
| # compare new node with it's parent | ||
| # if they are out of order swap and heap-up using the parent's index number | ||
| parent = (index - 1) / 2 | ||
| if @store[index].key < @store[parent].key # if current < parent, swap | ||
| swap(index, parent) | ||
| # recursion base case: if we hit root or if parent value < current node value | ||
| heap_up(parent) | ||
| end | ||
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| end | ||
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| # This helper method takes an index and | ||
| # moves it up the heap if it's smaller | ||
| # moves it down the heap if it's larger | ||
| # than it's parent node. | ||
| def heap_down(index) | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 |
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| raise NotImplementedError, "Method not implemented yet..." | ||
| # base case: until current doesn't have children || max child < array[current] | ||
| left_child = 2 * index + 1 | ||
| right_child = 2 * index + 2 | ||
| max_child = @store.size | ||
| return if index == (max_child) | ||
| if @store[left_child] && @store[right_child] # if both children | ||
| min_child = [@store[left_child].key, @store[right_child].key].min | ||
| if min_child == @store[left_child].key # if left to right order, swap left and heap down left | ||
| swap(left_child, index) | ||
| heap_down(left_child) | ||
| else | ||
| swap(right_child, index) | ||
| heap_down(right_child) | ||
| end | ||
| elsif @store[left_child] # there must be a left child | ||
| if @store[left_child].key < @store[index].key | ||
| swap(left_child, index) | ||
| heap_down(left_child) | ||
| else | ||
| swap(right_child, index) | ||
| heap_down(right_child) | ||
| end | ||
| end | ||
| return | ||
| end | ||
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| # If you want a swap method... you're welcome | ||
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