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🧷 문제 링크
https://www.acmicpc.net/problem/2225
🧭 풀이 시간
40분
👀 체감 난이도
✏️ 문제 설명
n과 k가 주어졌을 때 0부터 n까지의 수 k개를 더해서 n이 되는 경우의 수를 구하는 문제입니다.
덧셈의 순서가 바뀌면 다른 경우로 세며 하나의 수를 여러번 사용할 수 있습니다.
🔍 풀이 방법
DP를 활용해서 풀었습니다. dp[i][j] 에서 i개의 수를 써서 j를 만들 수 있는 경우의 수를 구했습니다.
⏳ 회고
간단한 dp 였던 것 같았는데 점화식이 생각이 잘 나지 않았습니다