docs: Add comment re expr_call duplication#4638
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Not sure why this doesn't work. We don't necessarily need to merge this but pushing in case anyone knows offhand...
max-sixty
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expr_call duplicationexpr_call duplication
aljazerzen
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Jun 21, 2024
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| // This simply inlines `expr_call`. But if we call `expr_call` here, we get a | ||
| // stack overflow — possibly because this is a recursive parser? | ||
| // let nested_expr = pipeline(expr_call().boxed()).boxed(); |
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It's not exactly an inline:
- the
exprin this function is the reference to the "recursive" node, - the
exprinexpr_call()is the whole expr parser, reconstructed.
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To be fair the is the most confusing part of the parser (and prql cfg).
It stems from the fact that some locations is PRQL allow "expression that can have function calls at top-level" and other locations allow only "expression that don't have function calls at top-level".
For example:
let a = ____is the first case,join ____ (owner==id)is the second case. Here, the___cannot be expr with function calls at the top-level (for examplefrom db.mytable) because that would also consume the last argument tojoin. It would parse as(join (from db.mytable (owner==id))instead of(join (from db.mytable) (owner==id).
This stems from the fact that we don't require parenthesis for func calls or even commas.
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Not sure why this doesn't work. We don't necessarily need to merge this but pushing in case anyone knows offhand...