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108 changes: 108 additions & 0 deletions ciphers/two_square_cipher.py
Original file line number Diff line number Diff line change
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def generate_square(keyword: str) -> list:

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As there is no test file in this pull request nor any test function or class in the file ciphers/two_square_cipher.py, please provide doctest for the function generate_square

"""
Generate a 5x5 Playfair square (I/J combined) from a keyword.
"""
keyword = keyword.upper().replace("J", "I")
seen = set()
square = []
for char in keyword:
if char.isalpha() and char not in seen:
seen.add(char)
square.append(char)
for char in "ABCDEFGHIKLMNOPQRSTUVWXYZ":
if char not in seen:
seen.add(char)
square.append(char)
return [square[i : i + 5] for i in range(0, 25, 5)]


def find_position(square, char):

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As there is no test file in this pull request nor any test function or class in the file ciphers/two_square_cipher.py, please provide doctest for the function find_position

Please provide return type hint for the function: find_position. If the function does not return a value, please provide the type hint as: def function() -> None:

Please provide type hint for the parameter: square

Please provide type hint for the parameter: char

"""
Return (row, col) of char in given 5x5 square.
"""
if char == "J":
char = "I"
for r in range(5):
for c in range(5):
if square[r][c] == char:
return r, c
return None


def two_square_encrypt(plaintext: str, key1: str, key2: str) -> str:
"""
Encrypt plaintext using the Two-Square cipher.

>>> two_square_encrypt("HELLO", "KEYWORD", "EXAMPLE")
'CEYLBX'
"""
plaintext = plaintext.upper().replace("J", "I")
plaintext = "".join([c for c in plaintext if c.isalpha()])

# split into digraphs
pairs = []
i = 0
while i < len(plaintext):
a = plaintext[i]
b = plaintext[i + 1] if i + 1 < len(plaintext) else "X"
if a == b:
b = "X"
i += 1
else:
i += 2
pairs.append((a, b))

square1 = generate_square(key1)
square2 = generate_square(key2)

ciphertext = ""
for a, b in pairs:
r1, c1 = find_position(square1, a)
r2, c2 = find_position(square2, b)
ciphertext += square2[r1][c2]
ciphertext += square1[r2][c1]
return ciphertext


def two_square_decrypt(ciphertext: str, key1: str, key2: str) -> str:
"""
Decrypt ciphertext using the Two-Square cipher.

>>> two_square_decrypt("CEYLBX", "KEYWORD", "EXAMPLE")
'HELLOX'
"""
ciphertext = ciphertext.upper().replace("J", "I")
ciphertext = "".join([c for c in ciphertext if c.isalpha()])

if len(ciphertext) % 2 != 0:
raise ValueError("Ciphertext must have even length")

square1 = generate_square(key1)
square2 = generate_square(key2)

plaintext = ""
for i in range(0, len(ciphertext), 2):
a, b = ciphertext[i], ciphertext[i + 1]
r1, c1 = find_position(square2, a)
r2, c2 = find_position(square1, b)
plaintext += square1[r1][c2]
plaintext += square2[r2][c1]
return plaintext


if __name__ == "__main__":
from doctest import testmod

testmod()

# Example usage
plaintext = "HELLO"
key1 = "KEYWORD"
key2 = "EXAMPLE"
encrypted = two_square_encrypt(plaintext, key1, key2)
decrypted = two_square_decrypt(encrypted, key1, key2)

print("\n\n")
print("Plaintext:", plaintext)
print("Encrypted:", encrypted)
print("Decrypted:", decrypted)
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