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prgmr99
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Feb 26, 2026
| expect(chunk([1, 2, 3], 0)).toEqual([[1], [2], [3]]); | ||
| expect(chunk([1, 2, 3], Number.NaN)).toEqual([[1], [2], [3]]); | ||
| }); | ||
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chunk([1,2,3], 2)는 [1,2], [3] 이 되나요??
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맞아요! 기대결과가 그렇게 나올겁니다!
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성능이 중요한 메서드들을 따로 성능 측정하는 코드인가요??
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